# How do you solve 3^x=14?

The answer is: $\ln \frac{14}{\ln} 3$.
You have to put both members as argument of a logarithm, it's better in the $e$ base.
$\ln {3}^{x} = \ln 14 \Rightarrow x \ln 3 = \ln 14 \Rightarrow x = \ln \frac{14}{\ln} 3$.