How do you solve #3^(x-2)=27#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Don't Memorise May 23, 2015 #3^(x-2)=27# 27 can be written as #3^3# #3^(x-2)=3^3# at this stage exponents can be equated #x-2 = 3# #color(blue)( x = 5# is the solution for the expression. Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 5107 views around the world You can reuse this answer Creative Commons License