# How do you solve 3(x-2)ln2=99?

$x = 2 + \frac{33}{\ln} 2$
$3 \left(x - 2\right) \cdot \ln 2 = 99 \implies \left(x - 2\right) = \frac{99}{3 \ln 2} \implies x - 2 = \frac{33}{\ln} 2 \implies x = 2 + \frac{33}{\ln} 2$