# How do you solve 3(x + 2) > x?

Apr 14, 2018

x>-3.

#### Explanation:

$3 \left(x + 2\right) > x$
=> $3 x + 6 > x$
=> $3 x + 6 - x > x - x$ ; (subtract x from both sides)
=>$2 x + 6 > 0$
=>$2 x + 6 - 6 > 0 - 6$; (subtract 6 from both sides)
=> 2x > -6
now finally divide by 2 on both sides to get,
=> $x > - 3$

Apr 14, 2018

$x > - 3$

#### Explanation:

Expand:

$3 \left(x + 2\right) > x \to 3 x + 6 > x$

Get $x$ on one side, then minus $6$

$3 x + 6 > x \to 2 x > - 6$

Divide by $2$:

$x > - 3$

Remember what we do on one side, we do to the other. Use this when doing all the steps above