# How do you solve (3/x + 2/x) >( 1- 4/x)?

Jul 1, 2017

See below.

#### Explanation:

Before we do anything, we must remember that $x$ cannot be zero, as it causes the denominator of the fractions to be zero.

$\left(\frac{3}{x} + \frac{2}{x}\right) = \frac{5}{x}$

$\frac{5}{x} > 1 - \frac{4}{x}$

$\frac{9}{x} > 1$

$9 > x$, where $x \setminus \ne 0$ (or $\left(- \infty , 0\right) \setminus \cup \left(0 , 9\right)$).