How do you solve #3(x-5)^2 + 8 = 14#? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer Ratnaker Mehta Jul 7, 2016 #x=5+-sqrt2.# #x~=6.414#, or, #x~=3.586# Explanation: #3(x-5)^2+8=14.# #:. 3(x-5)^2=14-8=6.# #:. (x-5)^2=6/3=2.# #:. (x-5)=+-sqrt2.# #:. x=5+-sqrt2.# Taking, #sqrt2=1.414, x~=5+-1.414.# #:. x~=5+1.414=6.414#, or, #x~=5-1.414=3.586# Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve #-3x^2+12x+1=0#? How do you solve #-4x^2+4x=9#? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation #81x^2+1=0#? How do you solve #-4x^2+4000x=0#? How do you solve for x in #x^2-6x+4=0#? How do you solve #x^2-6x-16=0# by factoring? How do you solve by factoring and using the principle of zero products #x^2 + 7x + 6 = 0#? How do you solve #x^2=2x#? See all questions in Comparing Methods for Solving Quadratics Impact of this question 1018 views around the world You can reuse this answer Creative Commons License