How do you solve #30< 5( x + 6) < 85#?

1 Answer
May 2, 2017

See the entire solution process below:

Explanation:

First, divide each segment of the system of equation by #color(red)(5)# to eliminate the term outside the parenthesis while keeping the system balanced:

#30/color(red)(5) < (5(x + 6))/color(red)(5) < 85/color(red)(5)#

#6 < (color(red)(cancel(color(black)(5)))(x + 6))/cancel(color(red)(5)) < 17#

#6 < x + 6 < 17#

Now, subtract #color(red)(6)# from each segment to solve for #x# while keeping the system balanced:

#6 - color(red)(6) < x + 6 - color(red)(6) < 17 - color(red)(6)#

#0 < x + 0 < 11#

#0 < x < 11#

Or

#x > 0# and #x < 11#

Or, in interval notation:

#(0, 11)#