How do you solve #3000/(2+e^(2x))=2#?

1 Answer
Bill K.
Jan 14, 2017

The answer is #x=1/2 ln(1498)=ln(sqrt(1498))approx 3.65594#

Explanation:

First, multiply both sides by #2+e^(2x)# and divide both sides by 2 to get #2+e^(2x)=1500.# Subtracting 2 from both sides leads to #e^(2x)=1498#. Now take the natural logarithm of both sides and then divide both sides by 2 to get the final answer:

#x=1/2 ln(1498)=ln(sqrt(1498))approx 3.65594#.

Related questions
See all questions in Logarithmic Models
Impact of this question
1343 views around the world
You can reuse this answer
Creative Commons License