Question

How do you solve `35x^ + 98x + 40=0`?

Answer 1

Assuming the intended equation was `35x^2+98x+40=0`, use the quadratic formula to find:

`x=-7/5+-sqrt(1001)/35`

Explanation:

`35x^2+98x+40` is of the form `ax^2+bx+c` with `a=35`, `b=98` and `c=40`.

This has zeros given by the quadratic formula:

`x=(-b+-sqrt(b^2-4ac))/(2a)=(-98+-sqrt(98^2-(4*35*40)))/(2*35)=-7/5+-sqrt(49^2-1400)/35`

`=-7/5+-sqrt(1001)/35`