How do you solve #38+5x >7 (x+4)#?

2 Answers

Answer:

#x<5#

Explanation:

#38+5x>7x+28#

#5x-7x> -38+28#

#-2x> -10#

#2x<10#

#x<5#

Aug 10, 2018

Answer:

#x<5#

Explanation:

First, let's switch the sides:

#7(x+4)<5x+38#

Next, we can distribute the #7# on the left to get

#7x+28<5x+38#

Next, subtract #5x# from both sides to get

#2x+28<38#

We can subtract #28# from both sides to get

#2x<10#

Lastly, we divide both sides by #2# to get

#x<5#

Hope this helps!