How do you solve #3a+ 6\leq - 5( a+ 2)#?

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Answer 1 · 2018-07-22T19:36:19

#a\le -2#

Given inequality:

#3a+6\le -5(a+2)#

#3a+6\le -5a-10#

#3a+6+5a\le -5a-10+5a#

#8a+6\le -10#

#8a+6-6\le-10-6#

#8a\le-16#

#{8a}/8\le -16/8#

#a\le -2#

Answer 2 · 2018-07-22T20:01:50

#a<=-2#

Let's start by distributing the #-5# on the right side. We now have

#3a+6<=-5a-10#

Next, let's add #5a# to both sides to get

#8a+6<=-10#

We can subtract #6# from both sides to get

#8a<=-16#

Dividing both sides by #8#, we get

#a<=-2#

Hope this helps!