# How do you solve 3e^(-b)=56?

Sep 21, 2016

$b = - 2.9268$

#### Explanation:

As $3 {e}^{- b} = 56$, we have

$\frac{3}{e} ^ b = 56$ or

$3 = 56 {e}^{b}$ or

${e}^{b} = \frac{3}{56}$ and taking natural logarithm on both sides

$b = \ln 3 - \ln 56 = 1.0986 - 4.0254 = - 2.9268$