How do you solve #3e^x=122#?

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Answer 1 · 2016-06-09T11:21:21

Using the logarithm.

The way to "pull down" the #x# from an exponential is to use the inverse function that is the logarithm.

#3e^x=122#

#e^x=122/3#

Then we apply the logarithm on both sides

#ln(e^x)=ln(122/3)#

Because the logarithm is the inverse of the exponential, they cancel each other on the left

#x=ln(122/3)\approx3.7#.