# How do you solve (3n - 2) (4n + 1) = 0 by factoring?

Mar 20, 2018

$n = - \frac{1}{4} \text{ or } n = \frac{2}{3}$

#### Explanation:

$\text{since the product of the factors is zero then one or both of}$
$\text{the factors must equal zero}$

$\text{to solve equate each factor to zero and solve for n}$

$3 n - 2 = 0 \Rightarrow n = \frac{2}{3}$

$4 n + 1 = 0 \Rightarrow n = - \frac{1}{4}$