How do you solve #3p - 1< 5#?

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Answer 1 · 2018-07-24T18:51:10

#p < 2#

#3p - 1 < 5#

Add #color(blue)1# to both sides:
#3p - 1 quadcolor(blue)(+quad1) < 5 quadcolor(blue)(+quad1)#

#3p < 6#

Divide both sides by #color(blue)3#:
#(3p)/color(blue)3 < 6/color(blue)3#

#p < 2#

Here's a graph of it on a number line:
enter image source here
(mathwarehouse.com)

The open circle on #2# means that #2# is not a solution (but anything else less than it is).

Hope this helps!