# How do you solve 3q+11=-1?

Jul 27, 2016

$\textcolor{p u r p \le}{\text{q= - 4}}$

#### Explanation:

$\textcolor{c \mathmr{and} a l}{\text{Subtract 11 on both sides:}}$

$3 q + \cancel{11} = - 1$
$\textcolor{w h i t e}{a a} - \cancel{11} - 11$

11 cancels out on the left side, and when you subtract 11 from -1 on the right side you obtain -12:

$3 q = - 12$

$\textcolor{g r e e n}{\text{Divide both sides 3 to get q by itself.}}$

$\frac{\cancel{\text{3}} q}{\cancel{3}} = \frac{- 12}{3}$

Now you are just left with $q$ on the left side and -4 on the right side.

Thus,
$\textcolor{red}{\text{q = - 4}}$