How do you solve #3t + 10= 19#?

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Answer 1 · 2016-12-20T13:10:12

#t = 3#

First, isolate the #t# term while keeping the equation balanced:

#3t + 10 - color(red)(10) = 19 - color(red)(10)#

#3t + 0 = 9#

#3t = 9#

Now, solve for #t# while keeping the equation balanced:

#(3t)/color(red)(3) = 9/color(red)(3)#

#(color(red)(cancel(color(black)(3)))t)/color(red)(cancel(color(black)(3))) = 3#

#t = 3#