Question

How do you solve `(3x-1)^2 = 12` using the square root property?

Answer 1

When a square is equal to a number, there are two answers:

Explanation:

`3x-1=sqrt12or3x-1=-sqrt12`
because both `sqrt12and-sqrt12` give `12` when squared.

Since `sqrt12=2sqrt3->`

`3x=1+-2sqrt3->x_(1,2)=(1+-2sqrt3)/3=1/3+-2/3sqrt3`