How do you solve (3x - 1) ^ { 2} = 5? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer Juan A. ยท Stefan V. Mar 17, 2017 x =(+- sqrt(5) +1)/ 3 Explanation: (3x -1)^2 = 5 3x -1 = +- sqrt(5) 3x = +- sqrt(5) + 1 x =(+- sqrt(5) + 1)/ 3 Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve -3x^2+12x+1=0? How do you solve -4x^2+4x=9? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation 81x^2+1=0? How do you solve -4x^2+4000x=0? How do you solve for x in x^2-6x+4=0? How do you solve x^2-6x-16=0 by factoring? How do you solve by factoring and using the principle of zero products x^2 + 7x + 6 = 0? How do you solve x^2=2x? See all questions in Comparing Methods for Solving Quadratics Impact of this question 1682 views around the world You can reuse this answer Creative Commons License