# How do you solve (3x - 1) ^ { 2} = 5?

Mar 17, 2017

$x = \frac{\pm \sqrt{5} + 1}{3}$

#### Explanation:

${\left(3 x - 1\right)}^{2} = 5$

$3 x - 1 = \pm \sqrt{5}$

$3 x = \pm \sqrt{5} + 1$

$x = \frac{\pm \sqrt{5} + 1}{3}$