How do you solve #3x + 16= x#?

3 Answers
Apr 15, 2018

#x=-8#

Explanation:

We can begin by subtracting #3x# from both sides. Here, we want to get #x# on one side, and it'll be easier to get it on the right hand side. We get:

#16=-2x#

We can divide both sides by #-2# to get:

#x=-8#

#x=-8#

Explanation:

Okay, so what you do here is isolate the variable, #x#. That would make the equation,

#-2x=16#

Now, divide both sides by #-2# and you'll get your answer.

#x=-8#

Apr 15, 2018

#x=-8#

Explanation:

#"collect terms in x on the left side and numeric values"#
#"on the right side of the equation"#

#"subtract x from both sides"#

#3x-x+16=cancel(x)cancel(-x)#

#rArr2x+16=0#

#"subtract 16 from both sides"#

#2xcancel(+16)cancel(-16)=0-16#

#rArr2x=-16#

#"divide both sides by 2"#

#(cancel(2) x)/cancel(2)=(-16)/2#

#rArrx=-8#

#color(blue)"As a check"#

Substitute this value into the equation and if both sides are equal then it is the solution.

#(3xx-8)+16=-24+16=-8=" right side"#

#rArrx=-8" is the solution"#