Question

How do you solve `3x + 16= x`?

Answer 1

`x=-8`

Explanation:

We can begin by subtracting `3x` from both sides. Here, we want to get `x` on one side, and it'll be easier to get it on the right hand side. We get:

`16=-2x`

We can divide both sides by `-2` to get:

`x=-8`

Answer 2

`x=-8`

Explanation:

Okay, so what you do here is isolate the variable, `x`. That would make the equation,

`-2x=16`

Now, divide both sides by `-2` and you'll get your answer.

`x=-8`

Answer 3

`x=-8`

Explanation:

`"collect terms in x on the left side and numeric values"`
`"on the right side of the equation"`

`"subtract x from both sides"`

`3x-x+16=cancel(x)cancel(-x)`

`rArr2x+16=0`

`"subtract 16 from both sides"`

`2xcancel(+16)cancel(-16)=0-16`

`rArr2x=-16`

`"divide both sides by 2"`

`(cancel(2) x)/cancel(2)=(-16)/2`

`rArrx=-8`

`color(blue)"As a check"`

Substitute this value into the equation and if both sides are equal then it is the solution.

`(3xx-8)+16=-24+16=-8=" right side"`

`rArrx=-8" is the solution"`