# How do you solve 3x + 2 ≤ 1?

Sep 1, 2015

$x \le - \frac{1}{3}$

#### Explanation:

Things you can do with expressions in an inequality which maintain the inequality:

• Add the same amount to each expression
• Subtract the same amount from each expression
• Divide each expression by the same amount provided the amount is greater than zero
• Multiply each expression by the same amount provided the amount is greater than zero

Therefore, given
$\textcolor{w h i t e}{\text{XXX}} 3 x + 2 \le 1$

We can subtract $2$ from both sides:
$\textcolor{w h i t e}{\text{XXX}} 3 x \le - 1$

and, we can divide both sides by $3$
$\textcolor{w h i t e}{\text{XXX}} x \le - \frac{1}{3}$