How do you solve #3x + 2 ≤ 1#?

1 Answer
Sep 1, 2015

Answer:

#x <= -1/3#

Explanation:

Things you can do with expressions in an inequality which maintain the inequality:

  • Add the same amount to each expression
  • Subtract the same amount from each expression
  • Divide each expression by the same amount provided the amount is greater than zero
  • Multiply each expression by the same amount provided the amount is greater than zero

Therefore, given
#color(white)("XXX")3x+2 <= 1#

We can subtract #2# from both sides:
#color(white)("XXX")3x <= -1#

and, we can divide both sides by #3#
#color(white)("XXX")x <= -1/3#