Question

How do you solve `-3x^2 –10 x + 8 = 0`?

Answer 1

Solve y = -3x^2 - 10x + 8 = 0
Ans: `2/3` and -4

Explanation:

y = - 3x^2 - 10x + 8 = 0 (!)
I use the new Transforming Method (Google, Yahoo Search)
Transformed y' = x^2 - 10x - 24. = 0 (2) Roots have opposite signs.
Factor pairs of (-24) --> (-2, 12). This sum is 10 = -b. Then, the 2 real roots of (2) are: -2 and 12.
Back to equation (1). the 2 real roots are: `(-2)/-3 = 2/3` and `12/-3 = -4.`