# How do you solve -3x^2 –10 x + 8 = 0 ?

Aug 1, 2015

Solve y = -3x^2 - 10x + 8 = 0
Ans: $\frac{2}{3}$ and -4

#### Explanation:

y = - 3x^2 - 10x + 8 = 0 (!)
I use the new Transforming Method (Google, Yahoo Search)
Transformed y' = x^2 - 10x - 24. = 0 (2) Roots have opposite signs.
Factor pairs of (-24) --> (-2, 12). This sum is 10 = -b. Then, the 2 real roots of (2) are: -2 and 12.
Back to equation (1). the 2 real roots are: $\frac{- 2}{-} 3 = \frac{2}{3}$ and $\frac{12}{-} 3 = - 4.$