How do you solve #-3x^2+12=0#?

1 Answer
Mar 25, 2016

Answer:

x=2

Explanation:

-3x^2+12=0
When solving an equation for a variable it is important to go in reverse order of operations. You have to undo everything in the equation.
Subtract 12 from each side:
-3x^2+12-12=0-12
Simplify:
-3x^2=-12
Next, divide both sides by -3:
(-3x^2)/-3=(-12)/-3
Simplify:
x^2=4
Now, undo the squared equation with a square root.
sqrt(x^2)=sqrt(4)
Simplify:
x=2