# How do you solve (3x-2)^2=(2x+6)^2?

Jan 19, 2017

$x = 8 , - \frac{4}{5}$
Taking square root on both sides, $3 x - 2 = \pm \left(2 x + 6\right)$
Next 3x-2= - (2x+6) would give $x = - \frac{4}{5}$