Question

How do you solve `(3x-2)^2=(2x+6)^2`?

Answer 1

`x=8, -4/5`

Explanation:

Taking square root on both sides, `3x-2= +- (2x+6)`

First 3x-2= 2x+6 would give x= 8

Next 3x-2= - (2x+6) would give `x= -4/5`