How do you solve #(3x+2)^2=9#?

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Answer 1 · 2016-07-06T15:38:44

#x = 1/3, -5/3# These are all of the solutions, but if you consider only the positive square root, then #x = 1/3# is the solution.

Take the square root of both sides

#sqrt((3x+2)^2) = sqrt9#

The square root of a value squared is that value and the square root of 9 is 3 and -3.

a) #3x+2 = 3#
b) #3x+2 = -3#

We have two equations since there are two values for the square root of 9. Isolate the variable and solve for #x#.

a) #3x = 1#
#x = 1/3#

b) #3x = -5#
#x = -5/3#

Solutions are: #x = 1/3, -5/3#