# How do you solve 3x^2 + 20x + 36 = 4 by completing the square?

May 7, 2015

$3 {x}^{2} + 20 x + 36 = 4$
3x^2+20x+36−4=4−4
$3 {x}^{2} + 20 x + 32 = 0$
$\left(3 x + 8\right) \left(x + 4\right) = 0$
$3 x + 8 = 0 \mathmr{and} x + 4 = 0$
x=−8/3 or x=−4