Question

How do you solve `3x^2 + 20x + 36 = 4` by completing the square?

Answer 1

Let's solve your equation step-by-step.
`3x^2+20x+36=4`
Step 1: Subtract 4 from both sides.
`3x^2+20x+36−4=4−4`
`3x^2+20x+32=0`
Step 2: Factor left side of equation.
`(3x+8)(x+4)=0`
Step 3: Set factors equal to 0.
`3x+8=0 or x+4=0`
#x=−8/3 or x=−4#