How do you solve #3x^2+4x=7# using the quadratic formula?

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Answer 1 · 2018-01-26T05:04:20

#x=1,-7/3#

#3x^2+4x=7#

Or, #3x^2+4x-7=0#.

The quadratic formula states that for every equation of the form #ax^2+bx+c=0#, where #a!=0#, #x=(-b+-sqrt(b^2-4ac))/(2a)#.

So input the values. Here, #a=3, b=4, c=-7#.

#(-4+-sqrt(4^2-4*3*-7))/(2*3)#

#(-4+-sqrt(16-(-84)))/(6)#

#-4+-sqrt(100)/6#

#x=(-4+10)/6,(-4-10)/6#

#x=6/6,-14/6#

#x=1,-7/3#