How do you solve #3x+2<=5(x-4)#?

1 Answer
Dec 10, 2016

Answer:

#x >= 22#

Explanation:

First, expand the terms within parenthesis:

#3x + 2 <= 5x - 20#

Now, isolate the #x# terms on one side of the inequality and the constants on the other while keeping the inequality balanced:

#3x - 3x + 2 + 20 <= 5x - 3x - 20 + 20#

#0 + 2 + 20 >= 5x - 3x - 0#

#22 <= 2x#

#22/2 <= (2x)/2#

#11 <= x#

Now to state in terms of #x# we need to reverse or "flip" the inequality:

#x >= 22#