How do you solve #3x^2+6x+3=0#?

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Answer 1 · 2016-04-02T17:29:11

The solution is:#color(blue)(x= -1 #

#3x^2 + 6x + 3 = 0#

The equation is of the form #color(blue)(ax^2+bx+c=0# where:
#a=3, b=6, c=3#

The Discriminant is given by:

#Delta=b^2-4*a*c#

# = (6)^2-(4* 3 * 3)#

# = 36 - 36 = 0 #

The solutions are found using the formula
#x=(-b+-sqrtDelta)/(2*a)#

#x=(-6+-sqrt0)/(2*3)#

#x=(-6+- 0)/( 6)#

#x=-6/6#

#color(blue)(x= -1 #