# How do you solve -3x^2=x-6 using the quadratic formula?

Convert into $a {x}^{2} + b x + c$ form.
$3 {x}^{2} + x - 6 = 0$
$a = 3 , b = 1 , c = - 6$
Plugging in gives: $\frac{- 1 + \sqrt{73}}{6} \mathmr{and} \frac{- 1 - \sqrt{73}}{6}$
Standard form is required to obtain a,b,c values for the quadratic formula. Standard form involves an equation in which one side is always equal to zero. In this example, we converted by adding $- 3 {x}^{2}$ to both sides.