How do you solve #3x - 3= 16x + 4#?

1 Answer
Jim G.
Dec 17, 2016

#x=-7/13#

Explanation:

Collect terms in x on one side of the equation and numeric values on the other side.

subtract 16x from both sides.

#3x-16x-3=cancel(16x)cancel(-16x)+4#

#rArr-13x-3=4#

add 3 to both sides.

#-13xcancel(-3)cancel(+3)=4+3#

#rArr-13x=7#

To solve for x, divide both sides by - 13

#(cancel(-13) x)/cancel(-13)=7/(-13)#

#rArrx=-7/13" is the solution"#

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