# How do you solve 3x-3<=6 ?

Mar 13, 2018

See a solution process below:

#### Explanation:

First, add $\textcolor{red}{3}$ to each side of the inequality to isolate the $x$ term while keeping the inequality balanced:

$3 x - 3 + \textcolor{red}{3} \le 6 + \textcolor{red}{3}$

$3 x - 0 \le 9$

$3 x \le 9$

Now, divide each side of the inequality by $\textcolor{red}{3}$ to solve for $x$ while keeping the inequality balanced:

$\frac{3 x}{\textcolor{red}{3}} \le \frac{9}{\textcolor{red}{3}}$

$\frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{3}}} x}{\cancel{\textcolor{red}{3}}} \le 3$

$x \le 3$