How do you solve #3x + 4< 22#?

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Answer 1 · 2016-12-05T04:15:52

#x<6#

#3x+4<22#

First, subtract 4 from both sides of the inequality.

#3x+4<22#
#3x-4<22-4#

This cancels out the 4, so the 3x is isolated.
#3x<18#

Next, divide both sides by 3 to further isolate the x.
#(3x)/3<18/3#

Finally, simplify to get the answer.

#x<6#