How do you solve #3x+(4-2x)=3#?

1 Answer
Dec 8, 2017

-1

Explanation:

the question is #3x + (4-2x) = 3# and what is the value of #x#?

This can be written as #3x +4 - 2x = 3# (open the parenthesis or brackets and as there is a plus sign outside the parenthesis, so the numbers inside it will retain their original signs of mathematical operation. Which is plus for 4 and minus for #2x#.

Now, keep the #x# terms on one side and the non-#x# or number terms on the other side of equal to sign. (Remember, whenever the side is changed, the mathematical operation sign also changes. In other words, on changing sides of to either side of equal to sign, plus becomes minus and vice-versa.)

So, #3x-2x = 3 -4# (see, the sign of 4 changed from plus to minus when it came to other side)
or, #x = -1#