# How do you solve 3x+4≥5x-8?

Jul 5, 2018

$x \le 6$

#### Explanation:

Let's subtract $5 x$ from both sides to get

$- 2 x + 4 \ge - 8$

Next, let's subtract $4$ from both sides to get

$- 2 x \ge - 12$

Next, we can divide both sides by $- 2$. Recall that when we multiply or divide an inequality by a negative, the sign flips.

We get:

$x \le 6$

Hope this helps!