How do you solve #3x+4≥5x-8#?

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Answer 1 · 2018-07-05T03:13:09

#x<= 6#

Let's subtract #5x# from both sides to get

#-2x+4>=-8#

Next, let's subtract #4# from both sides to get

#-2x>= -12#

Next, we can divide both sides by #-2#. Recall that when we multiply or divide an inequality by a negative, the sign flips.

We get:

#x<= 6#

Hope this helps!