# How do you solve -3x+4<-8#?

Apr 8, 2018

$x > 4$

#### Explanation:

Subtract $4$ from both sides

$- 3 x + 4 - 4 < - 8 - 4$

$- 3 x < - 12$

Divide both sides by $- 3$ (remember, when you divide or multiply both sides of an inequality by a negative, you have to flip the inequality sign)

$x > 4$