How do you solve (3x-5)(7x+8)=0?

May 21, 2016

Null Factor Law

Explanation:

$\left(3 x - 5\right) \left(7 x + 8\right) = 0$

According to null factor law, either one or both of those brackets are equal to 0, therefore

$\left(3 x - 5\right) = 0$ or $\left(7 x + 8\right) = 0$

Solve for $x$ in both equations
$3 x = 5$ or $7 x = - 8$
$x = \frac{5}{3}$ or $x = - \frac{8}{7}$