Question

How do you solve `-[ 3x + ( 5x + 3) ] = 9- ( 6x + 1)`?

Answer 1

`x=-\frac{11}{2}`

Explanation:

`-[3x+(5x+3)]=9-(6x+1)`

The first round brackets are preceded by the `+` sign, so they can be removed leaving the sign of the contained terms unchanged:
`-[3x+5x+3]=9-(6x+1)`

While for those preceded by the `-` we must invert the signs of terms:
`-[3x+5x+3]=9-6x-1`

Same reasoning for square brackets (`-` sign before):
`-3x-5x-3=9-6x-1`

Now let's move all the terms from the second part to the first part of equation changing the sign
`-3x-5x-3-9+6x+1=0`

Sum all terms with the `x` togheter and all the constants (terms whitout `x` toghter:
`-2x-11=0`

Move `-11` to the other side by changing the sign
`-2x=11`

Multiply both sides by `-1` to change the sign (the term x should be positive for readability):
`2x=-11`

Final result:
`x=-\frac{11}{2}`