How do you solve #3y - 1= 23- 3y#?

2 Answers
Sep 11, 2016

#y = 4#

Explanation:

We have: #3 y - 1 = 23 - 3 y#

Let's begin by adding #3 y# to both sides of the equation:

#=> 6 y - 1 = 23#

Then, let's add #1# to both sides:

#=> 6 y = 24#

Finally, to solve for #x#, let's divide both sides by #6#:

#=> y = 4#

Sep 11, 2016

#3y-1=23-3y#
shift the variable #-3y# to make it positive.
#3y+3y=23+1#
#6y=24#
#y=24/6#
#y=4#
Verification:
#3(4)-1=23-3(4)#
#12-1=23-12#
#11=11#