# How do you solve 3y - 1= 23- 3y?

Sep 11, 2016

$y = 4$

#### Explanation:

We have: $3 y - 1 = 23 - 3 y$

Let's begin by adding $3 y$ to both sides of the equation:

$\implies 6 y - 1 = 23$

Then, let's add $1$ to both sides:

$\implies 6 y = 24$

Finally, to solve for $x$, let's divide both sides by $6$:

$\implies y = 4$

Sep 11, 2016

$3 y - 1 = 23 - 3 y$
shift the variable $- 3 y$ to make it positive.
$3 y + 3 y = 23 + 1$
$6 y = 24$
$y = \frac{24}{6}$
$y = 4$
Verification:
$3 \left(4\right) - 1 = 23 - 3 \left(4\right)$
$12 - 1 = 23 - 12$
$11 = 11$