# How do you solve 3y ( 4y - 1) - 2y ( 6y - 5) = 9y - 8( 3+ y )?

Jan 3, 2017

$y = - 4$

#### Explanation:

First distribute everything:

$12 {y}^{2} - 3 y - 12 {y}^{2} + 10 y = 9 y - 24 - 8 y$

Then combine like terms:

$7 y = y - 24 \to$ the two $12 {y}^{2}$ terms cancel out

You can then subtract $y$ from both sides:

$6 y = - 24$

Then divide both sides by $- 14$ to get that

$y = \frac{- 24}{6} = - 4$