How do you solve #4^(12-3x)=64#?

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Answer 1 · 2015-08-17T12:58:19

#color(blue)(x=3#

#4^(12-3x)=64#

We know that #64=4^3#

Rewriting the expression we obtain:
#4^(12-3x)=4^3#

At this stage as bases are equal we equate the exponents to each other and find #x#
#12-3x=3#

#12-3=3x#

#9=3x#

#color(blue)(x=3#