# How do you solve 4^(12-3x)=64?

Aug 17, 2015

color(blue)(x=3

#### Explanation:

${4}^{12 - 3 x} = 64$

We know that $64 = {4}^{3}$

Rewriting the expression we obtain:
${4}^{12 - 3 x} = {4}^{3}$

At this stage as bases are equal we equate the exponents to each other and find $x$
$12 - 3 x = 3$

$12 - 3 = 3 x$

$9 = 3 x$

color(blue)(x=3