How do you solve #4^(12-3x)=64#?

1 Answer
Aug 17, 2015

Answer:

#color(blue)(x=3#

Explanation:

#4^(12-3x)=64#

We know that #64=4^3#

Rewriting the expression we obtain:
#4^(12-3x)=4^3#

At this stage as bases are equal we equate the exponents to each other and find #x#
#12-3x=3#

#12-3=3x#

#9=3x#

#color(blue)(x=3#