How do you solve #4( - 12d - 12) = 6( 8- 6d )#?

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Answer 1 · 2018-06-22T15:24:32

Use the distributive property, combine like terms, and divide.

The distributive property states that #a(b+c)=a*b+a*c#. Let's use this to simplify both sides:

#4(-12d-12)=4*-12d+4*-12=-48d-48#
#6(8-6d)=6*8+6*-6d=48-36d#

We now have #-48d-48=48-36d#. Next, let's combine like terms to isolate #d# on one side:

#-48d-48+48=48-36d+48#

#-48d=-36d+96#

#-48d+36d=-36d+96+36d#

#-12d=96#

Finally, let's divide each side by -12:

#(-12d)/-12=96/-12#
#d=-8#

Hope this helps!