How do you solve #4^(2p)=4^(-2p-1)#?

3 Answers

Answer:

#p=-1/4#

Explanation:

Given equation

#4^{2p}=4^{-2p-1}#

Comparing the powers on base #4# we get

#2p=-2p-1#

#2p+2p=-1#

#4p=-1#

#p=-1/4#

Jul 28, 2018

Answer:

#p=-1/4#

Explanation:

#"since both sides are expressed in base 4"#

#"we can equate the exponents"#

#2p=-2p-1#

#4p=-1rArrp=-1/4#

Jul 28, 2018

Answer:

#p=-1/4#

Explanation:

Since the bases are the same, we can equate the exponents. With this in mind, we now have:

#2p=-2p-1#

Next, let's add #2p# to both sides to get

#4p=-1#

Lastly, we can divide both sides by #4# to get

#p=-1/4#

Hope this helps!