# How do you solve #4( 2x - 3) \leq 2x - 17#?

##### 1 Answer

Sep 19, 2017

#### Explanation:

#"distribute the bracket, collect terms in x on the left side of"#

#"the inequality and numeric values on the right side"#

#8x-12<=2x-17#

#"subtract 2x from both sides"#

#8x-2x-12<=cancel(2x)cancel(-2x)-17#

#rArr6x-12<=-17#

#"add 12 to both sides"#

#6xcancel(-12)cancel(+12)<=-17+12#

#rArr6x<=-5#

#"divide both sides by 6"#

#(cancel(6) x)/cancel(6)<=(-5)/6#

#rArrx<=-5/6" is the solution"#