How do you solve #4( 2x - 3) \leq 2x - 17#?
1 Answer
Sep 19, 2017
Explanation:
#"distribute the bracket, collect terms in x on the left side of"#
#"the inequality and numeric values on the right side"#
#8x-12<=2x-17#
#"subtract 2x from both sides"#
#8x-2x-12<=cancel(2x)cancel(-2x)-17#
#rArr6x-12<=-17#
#"add 12 to both sides"#
#6xcancel(-12)cancel(+12)<=-17+12#
#rArr6x<=-5#
#"divide both sides by 6"#
#(cancel(6) x)/cancel(6)<=(-5)/6#
#rArrx<=-5/6" is the solution"#
