How do you solve #4( 2x + 4) + 4( 4x + 5) + 5= 24x + 42#?

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Answer 1 · 2018-03-02T15:14:23

No Solution

Breaking it down...

#4(2x+4) = 4*2x+4*4 = 8x+16#.

#4(4x+5) = 4*4x+4*5 = 16x+20#

#8x+16+16x+20+5=24x+42#

Combining Like Terms, #24x+41=24x+42#

Subtracting #41# from both sides,

#24x=24x+1#

Subtracting #24x# from Both Sides,

#0=0+1#, or #0=1#.

This is NOT Valid, so there is no Solution.

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