How do you solve #-4( 3x - 2) = - 32#?

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Answer 1 · 2016-09-11T00:18:44

#x=7/2#

Alternate answers: #x=3 1/2# or #x=3.5#

#-4(3x-2)=-32#

Expand the left-hand side.

#-12x+8=-32#

Subtract #8# from both sides.

#-12x = -32-8#

Simplify.

#-12x = -40#

Divide both sides by #-12#.

#x = (-40)/(-12)#

Simplify.

#x = 42/12#

Divide the numerator and denominator by #6#.

#=(42/6)/(12/6)#

Simplify.

#x=7/2#