How do you solve 4^ { 3x - 9} - 10= - 343x910=3?

1 Answer
Mar 28, 2018

x = {log_4(7) + 9}/3 approx 4.4x=log4(7)+934.4

Explanation:

4^{3x -9} - 10 = -343x910=3

4^{3x -9} = 743x9=7 //add 10 to both sides

3x -9 = log_(4) 73x9=log47 //log_4log4 on both sides (log_a(a^{x})=xloga(ax)=x)

3x = log_4(7) + 93x=log4(7)+9 //add 9 to both sides

x = {log_4(7) + 9}/3x=log4(7)+93 //divide both sides by 3