How do you solve 4^ { 3x - 9} - 10= - 3? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Carl S. Mar 28, 2018 x = {log_4(7) + 9}/3 approx 4.4 Explanation: 4^{3x -9} - 10 = -3 4^{3x -9} = 7 //add 10 to both sides 3x -9 = log_(4) 7 //log_4 on both sides (log_a(a^{x})=x) 3x = log_4(7) + 9 //add 9 to both sides x = {log_4(7) + 9}/3 //divide both sides by 3 Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve 9^(x-4)=81? How do you solve logx+log(x+15)=2? How do you solve the equation 2 log4(x + 7)-log4(16) = 2? How do you solve 2 log x^4 = 16? How do you solve 2+log_3(2x+5)-log_3x=4? See all questions in Logarithmic Models Impact of this question 1389 views around the world You can reuse this answer Creative Commons License