How do you solve #(4) ( - 5) ( - 2) ( - 3)#?
1 Answer
Nov 25, 2016
Explanation:
We should know the following facts with regard to
#color(blue)"signs"# when multiplying/dividing 2#color(blue)"integers."#
#• " both positive or both negative"rArr"positive result"#
#•" one positive and one negative"rArr"negative result"#
#rArr4xx(-5)xx(-2)xx(-3)# Calculate the first pair and second pair, then multiply
#=(color(red)(-20))xx(color(magenta)(+6))=-120#