# How do you solve 4(6x-1)^2-5=223?

$\frac{1 \pm \sqrt{57}}{6}$
$4 {\left(6 x - 1\right)}^{2} - 5 = 223$
${\left(6 x - 1\right)}^{2} = \frac{228}{4} = 57$
$\left(6 x - 1\right) = \pm \sqrt{57}$
$6 x = 1 + - \sqrt{57}$
$x = \frac{1 \pm \sqrt{57}}{6}$